-3(-7y+6)-6y=5(y-4)-2

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Solution for -3(-7y+6)-6y=5(y-4)-2 equation:



-3(-7y+6)-6y=5(y-4)-2
We move all terms to the left:
-3(-7y+6)-6y-(5(y-4)-2)=0
We add all the numbers together, and all the variables
-6y-3(-7y+6)-(5(y-4)-2)=0
We multiply parentheses
-6y+21y-(5(y-4)-2)-18=0
We calculate terms in parentheses: -(5(y-4)-2), so:
5(y-4)-2
We multiply parentheses
5y-20-2
We add all the numbers together, and all the variables
5y-22
Back to the equation:
-(5y-22)
We add all the numbers together, and all the variables
15y-(5y-22)-18=0
We get rid of parentheses
15y-5y+22-18=0
We add all the numbers together, and all the variables
10y+4=0
We move all terms containing y to the left, all other terms to the right
10y=-4
y=-4/10
y=-2/5

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