-3(-7y+9)-3y=2(y-7)-5

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Solution for -3(-7y+9)-3y=2(y-7)-5 equation: 



-3(-7y+9)-3y=2(y-7)-5

We move all terms to the left:

-3(-7y+9)-3y-(2(y-7)-5)=0

We add all the numbers together, and all the variables

-3y-3(-7y+9)-(2(y-7)-5)=0

We multiply parentheses

-3y+21y-(2(y-7)-5)-27=0



We calculate terms in parentheses: -(2(y-7)-5), so:

2(y-7)-5

We multiply parentheses

2y-14-5

We add all the numbers together, and all the variables

2y-19

Back to the equation:

-(2y-19)



We add all the numbers together, and all the variables

18y-(2y-19)-27=0

We get rid of parentheses

18y-2y+19-27=0

We add all the numbers together, and all the variables

16y-8=0

We move all terms containing y to the left, all other terms to the right

16y=8

y=8/16

y=1/2

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