-3(-8-4x)=40-2(4+3x)

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Solution for -3(-8-4x)=40-2(4+3x) equation: 



-3(-8-4x)=40-2(4+3x)

We move all terms to the left:

-3(-8-4x)-(40-2(4+3x))=0

We add all the numbers together, and all the variables

-3(-4x-8)-(40-2(3x+4))=0

We multiply parentheses

12x-(40-2(3x+4))+24=0



We calculate terms in parentheses: -(40-2(3x+4)), so:

40-2(3x+4)

determiningTheFunctionDomain
-2(3x+4)+40

We multiply parentheses

-6x-8+40

We add all the numbers together, and all the variables

-6x+32

Back to the equation:

-(-6x+32)



We get rid of parentheses

12x+6x-32+24=0

We add all the numbers together, and all the variables

18x-8=0

We move all terms containing x to the left, all other terms to the right

18x=8

x=8/18

x=4/9

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