-3(-8u+3)-6u=2(u-5)-1

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Solution for -3(-8u+3)-6u=2(u-5)-1 equation:



-3(-8u+3)-6u=2(u-5)-1
We move all terms to the left:
-3(-8u+3)-6u-(2(u-5)-1)=0
We add all the numbers together, and all the variables
-6u-3(-8u+3)-(2(u-5)-1)=0
We multiply parentheses
-6u+24u-(2(u-5)-1)-9=0
We calculate terms in parentheses: -(2(u-5)-1), so:
2(u-5)-1
We multiply parentheses
2u-10-1
We add all the numbers together, and all the variables
2u-11
Back to the equation:
-(2u-11)
We add all the numbers together, and all the variables
18u-(2u-11)-9=0
We get rid of parentheses
18u-2u+11-9=0
We add all the numbers together, and all the variables
16u+2=0
We move all terms containing u to the left, all other terms to the right
16u=-2
u=-2/16
u=-1/8

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