-3(-8x+4)-6x=2(x-4)-6

Solution for -3(-8x+4)-6x=2(x-4)-6 equation:

-3(-8x+4)-6x=2(x-4)-6

We move all terms to the left:

-3(-8x+4)-6x-(2(x-4)-6)=0

We add all the numbers together, and all the variables

-6x-3(-8x+4)-(2(x-4)-6)=0

We multiply parentheses

-6x+24x-(2(x-4)-6)-12=0


We calculate terms in parentheses: -(2(x-4)-6), so:

2(x-4)-6

We multiply parentheses

2x-8-6

We add all the numbers together, and all the variables

2x-14

Back to the equation:

-(2x-14)


We add all the numbers together, and all the variables

18x-(2x-14)-12=0

We get rid of parentheses

18x-2x+14-12=0

We add all the numbers together, and all the variables

16x+2=0

We move all terms containing x to the left, all other terms to the right

16x=-2

x=-2/16

x=-1/8