-3(-8y+3)-2y=7(y-2)-4

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Solution for -3(-8y+3)-2y=7(y-2)-4 equation: 



-3(-8y+3)-2y=7(y-2)-4

We move all terms to the left:

-3(-8y+3)-2y-(7(y-2)-4)=0

We add all the numbers together, and all the variables

-2y-3(-8y+3)-(7(y-2)-4)=0

We multiply parentheses

-2y+24y-(7(y-2)-4)-9=0



We calculate terms in parentheses: -(7(y-2)-4), so:

7(y-2)-4

We multiply parentheses

7y-14-4

We add all the numbers together, and all the variables

7y-18

Back to the equation:

-(7y-18)



We add all the numbers together, and all the variables

22y-(7y-18)-9=0

We get rid of parentheses

22y-7y+18-9=0

We add all the numbers together, and all the variables

15y+9=0

We move all terms containing y to the left, all other terms to the right

15y=-9

y=-9/15

y=-3/5

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