-3(-8y+7)-7y=5(y-3)-4

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Solution for -3(-8y+7)-7y=5(y-3)-4 equation: 



-3(-8y+7)-7y=5(y-3)-4

We move all terms to the left:

-3(-8y+7)-7y-(5(y-3)-4)=0

We add all the numbers together, and all the variables

-7y-3(-8y+7)-(5(y-3)-4)=0

We multiply parentheses

-7y+24y-(5(y-3)-4)-21=0



We calculate terms in parentheses: -(5(y-3)-4), so:

5(y-3)-4

We multiply parentheses

5y-15-4

We add all the numbers together, and all the variables

5y-19

Back to the equation:

-(5y-19)



We add all the numbers together, and all the variables

17y-(5y-19)-21=0

We get rid of parentheses

17y-5y+19-21=0

We add all the numbers together, and all the variables

12y-2=0

We move all terms containing y to the left, all other terms to the right

12y=2

y=2/12

y=1/6

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