-3(-8y+8)-7y=5(y-4)-1

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Solution for -3(-8y+8)-7y=5(y-4)-1 equation: 



-3(-8y+8)-7y=5(y-4)-1

We move all terms to the left:

-3(-8y+8)-7y-(5(y-4)-1)=0

We add all the numbers together, and all the variables

-7y-3(-8y+8)-(5(y-4)-1)=0

We multiply parentheses

-7y+24y-(5(y-4)-1)-24=0



We calculate terms in parentheses: -(5(y-4)-1), so:

5(y-4)-1

We multiply parentheses

5y-20-1

We add all the numbers together, and all the variables

5y-21

Back to the equation:

-(5y-21)



We add all the numbers together, and all the variables

17y-(5y-21)-24=0

We get rid of parentheses

17y-5y+21-24=0

We add all the numbers together, and all the variables

12y-3=0

We move all terms containing y to the left, all other terms to the right

12y=3

y=3/12

y=1/4

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