-3(-9x+1)-8x=4(x-4)-5

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Solution for -3(-9x+1)-8x=4(x-4)-5 equation: 



-3(-9x+1)-8x=4(x-4)-5

We move all terms to the left:

-3(-9x+1)-8x-(4(x-4)-5)=0

We add all the numbers together, and all the variables

-8x-3(-9x+1)-(4(x-4)-5)=0

We multiply parentheses

-8x+27x-(4(x-4)-5)-3=0



We calculate terms in parentheses: -(4(x-4)-5), so:

4(x-4)-5

We multiply parentheses

4x-16-5

We add all the numbers together, and all the variables

4x-21

Back to the equation:

-(4x-21)



We add all the numbers together, and all the variables

19x-(4x-21)-3=0

We get rid of parentheses

19x-4x+21-3=0

We add all the numbers together, and all the variables

15x+18=0

We move all terms containing x to the left, all other terms to the right

15x=-18

x=-18/15

x=-1+1/5

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