-3(-9x-4)-11=-6(x-12)-10

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Solution for -3(-9x-4)-11=-6(x-12)-10 equation: 



-3(-9x-4)-11=-6(x-12)-10

We move all terms to the left:

-3(-9x-4)-11-(-6(x-12)-10)=0

We multiply parentheses

27x-(-6(x-12)-10)+12-11=0



We calculate terms in parentheses: -(-6(x-12)-10), so:

-6(x-12)-10

We multiply parentheses

-6x+72-10

We add all the numbers together, and all the variables

-6x+62

Back to the equation:

-(-6x+62)



We add all the numbers together, and all the variables

27x-(-6x+62)+1=0

We get rid of parentheses

27x+6x-62+1=0

We add all the numbers together, and all the variables

33x-61=0

We move all terms containing x to the left, all other terms to the right

33x=61

x=61/33

x=1+28/33

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