-3(-r+2)-4r+3=3

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Solution for -3(-r+2)-4r+3=3 equation:



-3(-r+2)-4r+3=3
We move all terms to the left:
-3(-r+2)-4r+3-(3)=0
We add all the numbers together, and all the variables
-3(-1r+2)-4r+3-3=0
We add all the numbers together, and all the variables
-4r-3(-1r+2)=0
We multiply parentheses
-4r+3r-6=0
We add all the numbers together, and all the variables
-1r-6=0
We move all terms containing r to the left, all other terms to the right
-r=6
r=6/-1
r=-6

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