-3(-x+5)+20=-10(x-3)+4

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Solution for -3(-x+5)+20=-10(x-3)+4 equation: 



-3(-x+5)+20=-10(x-3)+4

We move all terms to the left:

-3(-x+5)+20-(-10(x-3)+4)=0

We add all the numbers together, and all the variables

-3(-1x+5)-(-10(x-3)+4)+20=0

We multiply parentheses

3x-(-10(x-3)+4)-15+20=0



We calculate terms in parentheses: -(-10(x-3)+4), so:

-10(x-3)+4

We multiply parentheses

-10x+30+4

We add all the numbers together, and all the variables

-10x+34

Back to the equation:

-(-10x+34)



We add all the numbers together, and all the variables

3x-(-10x+34)+5=0

We get rid of parentheses

3x+10x-34+5=0

We add all the numbers together, and all the variables

13x-29=0

We move all terms containing x to the left, all other terms to the right

13x=29

x=29/13

x=2+3/13

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