-3(1+2t)=7(t-5)

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Solution for -3(1+2t)=7(t-5) equation:



-3(1+2t)=7(t-5)
We move all terms to the left:
-3(1+2t)-(7(t-5))=0
We add all the numbers together, and all the variables
-3(2t+1)-(7(t-5))=0
We multiply parentheses
-6t-(7(t-5))-3=0
We calculate terms in parentheses: -(7(t-5)), so:
7(t-5)
We multiply parentheses
7t-35
Back to the equation:
-(7t-35)
We get rid of parentheses
-6t-7t+35-3=0
We add all the numbers together, and all the variables
-13t+32=0
We move all terms containing t to the left, all other terms to the right
-13t=-32
t=-32/-13
t=2+6/13

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