-3(1+5b)+6=-36-2b

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Solution for -3(1+5b)+6=-36-2b equation: 



-3(1+5b)+6=-36-2b

We move all terms to the left:

-3(1+5b)+6-(-36-2b)=0

We add all the numbers together, and all the variables

-3(5b+1)-(-2b-36)+6=0

We multiply parentheses

-15b-(-2b-36)-3+6=0

We get rid of parentheses

-15b+2b+36-3+6=0

We add all the numbers together, and all the variables

-13b+39=0

We move all terms containing b to the left, all other terms to the right

-13b=-39

b=-39/-13

b=+3

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