-3(1+6r)=33

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Solution for -3(1+6r)=33 equation: 



-3(1+6r)=33

We move all terms to the left:

-3(1+6r)-(33)=0

We add all the numbers together, and all the variables

-3(6r+1)-33=0

We multiply parentheses

-18r-3-33=0

We add all the numbers together, and all the variables

-18r-36=0

We move all terms containing r to the left, all other terms to the right

-18r=36

r=36/-18

r=-2

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