-3(1+7v)-8v=-8(2v-6)+1

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Solution for -3(1+7v)-8v=-8(2v-6)+1 equation: 



-3(1+7v)-8v=-8(2v-6)+1

We move all terms to the left:

-3(1+7v)-8v-(-8(2v-6)+1)=0

We add all the numbers together, and all the variables

-3(7v+1)-8v-(-8(2v-6)+1)=0

We add all the numbers together, and all the variables

-8v-3(7v+1)-(-8(2v-6)+1)=0

We multiply parentheses

-8v-21v-(-8(2v-6)+1)-3=0



We calculate terms in parentheses: -(-8(2v-6)+1), so:

-8(2v-6)+1

We multiply parentheses

-16v+48+1

We add all the numbers together, and all the variables

-16v+49

Back to the equation:

-(-16v+49)



We add all the numbers together, and all the variables

-29v-(-16v+49)-3=0

We get rid of parentheses

-29v+16v-49-3=0

We add all the numbers together, and all the variables

-13v-52=0

We move all terms containing v to the left, all other terms to the right

-13v=52

v=52/-13

v=-4

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