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-3(1+h=1/3(3-12h)
We move all terms to the left:
-3(1+h-(1/3(3-12h))=0
Domain of the equation: 3(3-12h))!=0We add all the numbers together, and all the variables
h∈R
-3(1+h-(1/3(-12h+3))=0
We multiply all the terms by the denominator
-3(1+h-(1=0
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