-3(1+n)-2=-6(n-2)

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Solution for -3(1+n)-2=-6(n-2) equation: 



-3(1+n)-2=-6(n-2)

We move all terms to the left:

-3(1+n)-2-(-6(n-2))=0

We add all the numbers together, and all the variables

-3(n+1)-(-6(n-2))-2=0

We multiply parentheses

-3n-(-6(n-2))-3-2=0



We calculate terms in parentheses: -(-6(n-2)), so:

-6(n-2)

We multiply parentheses

-6n+12

Back to the equation:

-(-6n+12)



We add all the numbers together, and all the variables

-3n-(-6n+12)-5=0

We get rid of parentheses

-3n+6n-12-5=0

We add all the numbers together, and all the variables

3n-17=0

We move all terms containing n to the left, all other terms to the right

3n=17

n=17/3

n=5+2/3

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