-3(1-10b)+5b=6(b-11)+5

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Solution for -3(1-10b)+5b=6(b-11)+5 equation: 



-3(1-10b)+5b=6(b-11)+5

We move all terms to the left:

-3(1-10b)+5b-(6(b-11)+5)=0

We add all the numbers together, and all the variables

-3(-10b+1)+5b-(6(b-11)+5)=0

We add all the numbers together, and all the variables

5b-3(-10b+1)-(6(b-11)+5)=0

We multiply parentheses

5b+30b-(6(b-11)+5)-3=0



We calculate terms in parentheses: -(6(b-11)+5), so:

6(b-11)+5

We multiply parentheses

6b-66+5

We add all the numbers together, and all the variables

6b-61

Back to the equation:

-(6b-61)



We add all the numbers together, and all the variables

35b-(6b-61)-3=0

We get rid of parentheses

35b-6b+61-3=0

We add all the numbers together, and all the variables

29b+58=0

We move all terms containing b to the left, all other terms to the right

29b=-58

b=-58/29

b=-2

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