-3(1-10b)+5b=6(b-11)+5

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Solution for -3(1-10b)+5b=6(b-11)+5 equation:



-3(1-10b)+5b=6(b-11)+5
We move all terms to the left:
-3(1-10b)+5b-(6(b-11)+5)=0
We add all the numbers together, and all the variables
-3(-10b+1)+5b-(6(b-11)+5)=0
We add all the numbers together, and all the variables
5b-3(-10b+1)-(6(b-11)+5)=0
We multiply parentheses
5b+30b-(6(b-11)+5)-3=0
We calculate terms in parentheses: -(6(b-11)+5), so:
6(b-11)+5
We multiply parentheses
6b-66+5
We add all the numbers together, and all the variables
6b-61
Back to the equation:
-(6b-61)
We add all the numbers together, and all the variables
35b-(6b-61)-3=0
We get rid of parentheses
35b-6b+61-3=0
We add all the numbers together, and all the variables
29b+58=0
We move all terms containing b to the left, all other terms to the right
29b=-58
b=-58/29
b=-2

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