-3(1-2b)-3b=5-(b-8)

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Solution for -3(1-2b)-3b=5-(b-8) equation: 



-3(1-2b)-3b=5-(b-8)

We move all terms to the left:

-3(1-2b)-3b-(5-(b-8))=0

We add all the numbers together, and all the variables

-3(-2b+1)-3b-(5-(b-8))=0

We add all the numbers together, and all the variables

-3b-3(-2b+1)-(5-(b-8))=0

We multiply parentheses

-3b+6b-(5-(b-8))-3=0



We calculate terms in parentheses: -(5-(b-8)), so:

5-(b-8)

determiningTheFunctionDomain
-(b-8)+5

We get rid of parentheses

-b+8+5

We add all the numbers together, and all the variables

-1b+13

Back to the equation:

-(-1b+13)



We add all the numbers together, and all the variables

3b-(-1b+13)-3=0

We get rid of parentheses

3b+1b-13-3=0

We add all the numbers together, and all the variables

4b-16=0

We move all terms containing b to the left, all other terms to the right

4b=16

b=16/4

b=4

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