-3(1-3b)-3=-33

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Solution for -3(1-3b)-3=-33 equation: 



-3(1-3b)-3=-33

We move all terms to the left:

-3(1-3b)-3-(-33)=0

We add all the numbers together, and all the variables

-3(-3b+1)-3-(-33)=0

We add all the numbers together, and all the variables

-3(-3b+1)+30=0

We multiply parentheses

9b-3+30=0

We add all the numbers together, and all the variables

9b+27=0

We move all terms containing b to the left, all other terms to the right

9b=-27

b=-27/9

b=-3

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