-3(1-6)=2(b+1)

Solution for -3(1-6)=2(b+1) equation:

-3(1-6)=2(b+1)

We move all terms to the left:

-3(1-6)-(2(b+1))=0

We add all the numbers together, and all the variables

-(2(b+1))-3(-5)=0

We add all the numbers together, and all the variables

-(2(b+1))+15=0


We calculate terms in parentheses: -(2(b+1)), so:

2(b+1)

We multiply parentheses

2b+2

Back to the equation:

-(2b+2)


We get rid of parentheses

-2b-2+15=0

We add all the numbers together, and all the variables

-2b+13=0

We move all terms containing b to the left, all other terms to the right

-2b=-13

b=-13/-2

b=6+1/2