-3(1-b)=2(b+2)

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Solution for -3(1-b)=2(b+2) equation: 



-3(1-b)=2(b+2)

We move all terms to the left:

-3(1-b)-(2(b+2))=0

We add all the numbers together, and all the variables

-3(-1b+1)-(2(b+2))=0

We multiply parentheses

3b-(2(b+2))-3=0



We calculate terms in parentheses: -(2(b+2)), so:

2(b+2)

We multiply parentheses

2b+4

Back to the equation:

-(2b+4)



We get rid of parentheses

3b-2b-4-3=0

We add all the numbers together, and all the variables

b-7=0

We move all terms containing b to the left, all other terms to the right

b=7

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