-3(1/5)d=-16

Solution for -3(1/5)d=-16 equation:

-3(1/5)d=-16

We move all terms to the left:

-3(1/5)d-(-16)=0


Domain of the equation: 5)d!=0

d!=0/1

d!=0

d∈R


We add all the numbers together, and all the variables

-3(+1/5)d-(-16)=0

We add all the numbers together, and all the variables

-3(+1/5)d+16=0

We multiply parentheses

-3d^2+16=0

a = -3; b = 0; c = +16;
Δ = b2-4ac
Δ = 02-4·(-3)·16
Δ = 192
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{192}=\sqrt{64*3}=\sqrt{64}*\sqrt{3}=8\sqrt{3}$
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{3}}{2*-3}=\frac{0-8\sqrt{3}}{-6}
=-\frac{8\sqrt{3}}{-6}
=-\frac{4\sqrt{3}}{-3}
$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{3}}{2*-3}=\frac{0+8\sqrt{3}}{-6}
=\frac{8\sqrt{3}}{-6}
=\frac{4\sqrt{3}}{-3}
$