-3(1z-4)-42=12(-5z+5)

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Solution for -3(1z-4)-42=12(-5z+5) equation: 



-3(1z-4)-42=12(-5z+5)

We move all terms to the left:

-3(1z-4)-42-(12(-5z+5))=0

We add all the numbers together, and all the variables

-3(z-4)-(12(-5z+5))-42=0

We multiply parentheses

-3z-(12(-5z+5))+12-42=0



We calculate terms in parentheses: -(12(-5z+5)), so:

12(-5z+5)

We multiply parentheses

-60z+60

Back to the equation:

-(-60z+60)



We add all the numbers together, and all the variables

-3z-(-60z+60)-30=0

We get rid of parentheses

-3z+60z-60-30=0

We add all the numbers together, and all the variables

57z-90=0

We move all terms containing z to the left, all other terms to the right

57z=90

z=90/57

z=1+11/19

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