-3(2)+6-5(2-1)=-5(2)-(2(2)-4)+5

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Solution for -3(2)+6-5(2-1)=-5(2)-(2(2)-4)+5 equation: 


Simplifying
-3(2) + 6 + -5(2 + -1) = -5(2) + -1(2(2) + -4) + 5

Multiply -3 * 2
-6 + 6 + -5(2 + -1) = -5(2) + -1(2(2) + -4) + 5

Combine like terms: 2 + -1 = 1
-6 + 6 + -5(1) = -5(2) + -1(2(2) + -4) + 5

Multiply -5 * 1
-6 + 6 + -5 = -5(2) + -1(2(2) + -4) + 5

Combine like terms: -6 + 6 = 0
0 + -5 = -5(2) + -1(2(2) + -4) + 5
-5 = -5(2) + -1(2(2) + -4) + 5

Multiply -5 * 2
-5 = -10 + -1(2(2) + -4) + 5

Multiply 2 * 2
-5 = -10 + -1(4 + -4) + 5

Combine like terms: 4 + -4 = 0
-5 = -10 + -1(0) + 5

Multiply -1 * 0
-5 = -10 + 0 + 5

Anything times zero is zero.
-5 = -10 + 0 + 5

Combine like terms: -10 + 0 = -10
-5 = -10 + 5

Combine like terms: -10 + 5 = -5
-5 = -5

Add '5' to each side of the equation.
-5 + 5 = -5 + 5

Combine like terms: -5 + 5 = 0
0 = -5 + 5

Combine like terms: -5 + 5 = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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