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-3(2+4x)=-7x^2
We move all terms to the left:
-3(2+4x)-(-7x^2)=0
We add all the numbers together, and all the variables
-(-7x^2)-3(4x+2)=0
We multiply parentheses
-(-7x^2)-12x-6=0
We get rid of parentheses
7x^2-12x-6=0
a = 7; b = -12; c = -6;
Δ = b2-4ac
Δ = -122-4·7·(-6)
Δ = 312
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{312}=\sqrt{4*78}=\sqrt{4}*\sqrt{78}=2\sqrt{78}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-2\sqrt{78}}{2*7}=\frac{12-2\sqrt{78}}{14} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+2\sqrt{78}}{2*7}=\frac{12+2\sqrt{78}}{14} $
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