-3(2+4x2)=2(2x2-1)

Solution for -3(2+4x2)=2(2x2-1) equation:

-3(2+4x^2)=2(2x^2-1)

We move all terms to the left:

-3(2+4x^2)-(2(2x^2-1))=0

We multiply parentheses

-12x^2-(2(2x^2-1))-6=0


We calculate terms in parentheses: -(2(2x^2-1)), so:

2(2x^2-1)

We multiply parentheses

4x^2-2

Back to the equation:

-(4x^2-2)


We get rid of parentheses

-12x^2-4x^2+2-6=0

We add all the numbers together, and all the variables

-16x^2-4=0

a = -16; b = 0; c = -4;
Δ = b2-4ac
Δ = 02-4·(-16)·(-4)
Δ = -256
Delta is less than zero, so there is no solution for the equation