-3(2-2r)+8=3r-7(r-6)

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Solution for -3(2-2r)+8=3r-7(r-6) equation:



-3(2-2r)+8=3r-7(r-6)
We move all terms to the left:
-3(2-2r)+8-(3r-7(r-6))=0
We add all the numbers together, and all the variables
-3(-2r+2)-(3r-7(r-6))+8=0
We multiply parentheses
6r-(3r-7(r-6))-6+8=0
We calculate terms in parentheses: -(3r-7(r-6)), so:
3r-7(r-6)
We multiply parentheses
3r-7r+42
We add all the numbers together, and all the variables
-4r+42
Back to the equation:
-(-4r+42)
We add all the numbers together, and all the variables
6r-(-4r+42)+2=0
We get rid of parentheses
6r+4r-42+2=0
We add all the numbers together, and all the variables
10r-40=0
We move all terms containing r to the left, all other terms to the right
10r=40
r=40/10
r=4

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