-3(2-7c)=3(2c-1)

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Solution for -3(2-7c)=3(2c-1) equation: 



-3(2-7c)=3(2c-1)

We move all terms to the left:

-3(2-7c)-(3(2c-1))=0

We add all the numbers together, and all the variables

-3(-7c+2)-(3(2c-1))=0

We multiply parentheses

21c-(3(2c-1))-6=0



We calculate terms in parentheses: -(3(2c-1)), so:

3(2c-1)

We multiply parentheses

6c-3

Back to the equation:

-(6c-3)



We get rid of parentheses

21c-6c+3-6=0

We add all the numbers together, and all the variables

15c-3=0

We move all terms containing c to the left, all other terms to the right

15c=3

c=3/15

c=1/5

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