-3(2/3m+4)=6

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Solution for -3(2/3m+4)=6 equation: 



-3(2/3m+4)=6

We move all terms to the left:

-3(2/3m+4)-(6)=0



Domain of the equation: 3m+4)!=0

m∈R



We multiply parentheses

-6m-12-6=0

We add all the numbers together, and all the variables

-6m-18=0

We move all terms containing m to the left, all other terms to the right

-6m=18

m=18/-6

m=-3

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