-3(2b+1)+(7b-5)=0

Solution for -3(2b+1)+(7b-5)=0 equation:

Simplifying
-3(2b + 1) + (7b + -5) = 0

Reorder the terms:
-3(1 + 2b) + (7b + -5) = 0
(1 * -3 + 2b * -3) + (7b + -5) = 0
(-3 + -6b) + (7b + -5) = 0

Reorder the terms:
-3 + -6b + (-5 + 7b) = 0

Remove parenthesis around (-5 + 7b)
-3 + -6b + -5 + 7b = 0

Reorder the terms:
-3 + -5 + -6b + 7b = 0

Combine like terms: -3 + -5 = -8
-8 + -6b + 7b = 0

Combine like terms: -6b + 7b = 1b
-8 + 1b = 0

Solving
-8 + 1b = 0

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '8' to each side of the equation.
-8 + 8 + 1b = 0 + 8

Combine like terms: -8 + 8 = 0
0 + 1b = 0 + 8
1b = 0 + 8

Combine like terms: 0 + 8 = 8
1b = 8

Divide each side by '1'.
b = 8

Simplifying
b = 8