-3(2b+1)+(7b-7)=0

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Solution for -3(2b+1)+(7b-7)=0 equation:


Simplifying
-3(2b + 1) + (7b + -7) = 0

Reorder the terms:
-3(1 + 2b) + (7b + -7) = 0
(1 * -3 + 2b * -3) + (7b + -7) = 0
(-3 + -6b) + (7b + -7) = 0

Reorder the terms:
-3 + -6b + (-7 + 7b) = 0

Remove parenthesis around (-7 + 7b)
-3 + -6b + -7 + 7b = 0

Reorder the terms:
-3 + -7 + -6b + 7b = 0

Combine like terms: -3 + -7 = -10
-10 + -6b + 7b = 0

Combine like terms: -6b + 7b = 1b
-10 + 1b = 0

Solving
-10 + 1b = 0

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '10' to each side of the equation.
-10 + 10 + 1b = 0 + 10

Combine like terms: -10 + 10 = 0
0 + 1b = 0 + 10
1b = 0 + 10

Combine like terms: 0 + 10 = 10
1b = 10

Divide each side by '1'.
b = 10

Simplifying
b = 10

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