-3(2b+1)+(7b-8)=0

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Solution for -3(2b+1)+(7b-8)=0 equation:


Simplifying
-3(2b + 1) + (7b + -8) = 0

Reorder the terms:
-3(1 + 2b) + (7b + -8) = 0
(1 * -3 + 2b * -3) + (7b + -8) = 0
(-3 + -6b) + (7b + -8) = 0

Reorder the terms:
-3 + -6b + (-8 + 7b) = 0

Remove parenthesis around (-8 + 7b)
-3 + -6b + -8 + 7b = 0

Reorder the terms:
-3 + -8 + -6b + 7b = 0

Combine like terms: -3 + -8 = -11
-11 + -6b + 7b = 0

Combine like terms: -6b + 7b = 1b
-11 + 1b = 0

Solving
-11 + 1b = 0

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '11' to each side of the equation.
-11 + 11 + 1b = 0 + 11

Combine like terms: -11 + 11 = 0
0 + 1b = 0 + 11
1b = 0 + 11

Combine like terms: 0 + 11 = 11
1b = 11

Divide each side by '1'.
b = 11

Simplifying
b = 11

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