-3(2b+2)+(7b-5)=0

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Solution for -3(2b+2)+(7b-5)=0 equation: 



-3(2b+2)+(7b-5)=0

We multiply parentheses

-6b+(7b-5)-6=0

We get rid of parentheses

-6b+7b-5-6=0

We add all the numbers together, and all the variables

b-11=0

We move all terms containing b to the left, all other terms to the right

b=11

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