-3(2b+4)+(7b-4)=0

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Solution for -3(2b+4)+(7b-4)=0 equation:


Simplifying
-3(2b + 4) + (7b + -4) = 0

Reorder the terms:
-3(4 + 2b) + (7b + -4) = 0
(4 * -3 + 2b * -3) + (7b + -4) = 0
(-12 + -6b) + (7b + -4) = 0

Reorder the terms:
-12 + -6b + (-4 + 7b) = 0

Remove parenthesis around (-4 + 7b)
-12 + -6b + -4 + 7b = 0

Reorder the terms:
-12 + -4 + -6b + 7b = 0

Combine like terms: -12 + -4 = -16
-16 + -6b + 7b = 0

Combine like terms: -6b + 7b = 1b
-16 + 1b = 0

Solving
-16 + 1b = 0

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '16' to each side of the equation.
-16 + 16 + 1b = 0 + 16

Combine like terms: -16 + 16 = 0
0 + 1b = 0 + 16
1b = 0 + 16

Combine like terms: 0 + 16 = 16
1b = 16

Divide each side by '1'.
b = 16

Simplifying
b = 16

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