-3(2b+4)+8=64

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Solution for -3(2b+4)+8=64 equation: 



-3(2b+4)+8=64

We move all terms to the left:

-3(2b+4)+8-(64)=0

We add all the numbers together, and all the variables

-3(2b+4)-56=0

We multiply parentheses

-6b-12-56=0

We add all the numbers together, and all the variables

-6b-68=0

We move all terms containing b to the left, all other terms to the right

-6b=68

b=68/-6

b=-11+1/3

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