-3(2c-4)+2c+12=-3c-17

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Solution for -3(2c-4)+2c+12=-3c-17 equation: 



-3(2c-4)+2c+12=-3c-17

We move all terms to the left:

-3(2c-4)+2c+12-(-3c-17)=0

We add all the numbers together, and all the variables

2c-3(2c-4)-(-3c-17)+12=0

We multiply parentheses

2c-6c-(-3c-17)+12+12=0

We get rid of parentheses

2c-6c+3c+17+12+12=0

We add all the numbers together, and all the variables

-1c+41=0

We move all terms containing c to the left, all other terms to the right

-c=-41

c=-41/-1

c=+41

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