-3(2c-5)=-4(c-3)

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Solution for -3(2c-5)=-4(c-3) equation: 



-3(2c-5)=-4(c-3)

We move all terms to the left:

-3(2c-5)-(-4(c-3))=0

We multiply parentheses

-6c-(-4(c-3))+15=0



We calculate terms in parentheses: -(-4(c-3)), so:

-4(c-3)

We multiply parentheses

-4c+12

Back to the equation:

-(-4c+12)



We get rid of parentheses

-6c+4c-12+15=0

We add all the numbers together, and all the variables

-2c+3=0

We move all terms containing c to the left, all other terms to the right

-2c=-3

c=-3/-2

c=1+1/2

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