-3(2i-5)=-6i+15

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Solution for -3(2i-5)=-6i+15 equation:



-3(2i-5)=-6i+15
We move all terms to the left:
-3(2i-5)-(-6i+15)=0
We multiply parentheses
-6i-(-6i+15)+15=0
We get rid of parentheses
-6i+6i-15+15=0
We add all the numbers together, and all the variables
=0
i=0/1
i=0

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