-3(2j/3)-6)=32

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Solution for -3(2j/3)-6)=32 equation: 



-3(2j/3)-6)=32

We move all terms to the left:

-3(2j/3)-6)-(32)=0

We add all the numbers together, and all the variables

-3(+2j/3)-6)-32=0

We add all the numbers together, and all the variables

-3(+2j/3)=0

We multiply parentheses

-6j=0

j=0/-6

j=0

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