-3(2k-3)+1=2(4k-2)+20-2k

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Solution for -3(2k-3)+1=2(4k-2)+20-2k equation:



-3(2k-3)+1=2(4k-2)+20-2k
We move all terms to the left:
-3(2k-3)+1-(2(4k-2)+20-2k)=0
We multiply parentheses
-6k-(2(4k-2)+20-2k)+9+1=0
We calculate terms in parentheses: -(2(4k-2)+20-2k), so:
2(4k-2)+20-2k
determiningTheFunctionDomain 2(4k-2)-2k+20
We add all the numbers together, and all the variables
-2k+2(4k-2)+20
We multiply parentheses
-2k+8k-4+20
We add all the numbers together, and all the variables
6k+16
Back to the equation:
-(6k+16)
We add all the numbers together, and all the variables
-6k-(6k+16)+10=0
We get rid of parentheses
-6k-6k-16+10=0
We add all the numbers together, and all the variables
-12k-6=0
We move all terms containing k to the left, all other terms to the right
-12k=6
k=6/-12
k=-1/2

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