-3(2k-4)+4(3k-5)-2+4k=

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Solution for -3(2k-4)+4(3k-5)-2+4k= equation:


-3(2k-4)+4(3k-5)-2+4k=0

We simplify the equation to the form, which is simple to understand 
-3(2k-4)+4(3k-5)-2+4k=0

Reorder the terms in parentheses
+(-6k+12)+4*(3k-5)-2+4k=0

Remove unnecessary parentheses
-6k+12+4+*(+3k-5+)-2+4k=0

Reorder the terms in parentheses
-6k+12+(+12k-20)-2+4k=0

Remove unnecessary parentheses
-6k+12+12k-20-2+4k=0

We move all terms containing k to the left and all other terms to the right. 
-6k+12k+4k=0-12+20+2

We simplify left and right side of the equation. 
+10k=+10

We divide both sides of the equation by 10 to get k. 
k=1

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