-3(2m-6)+7(m-3)=14-10

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Solution for -3(2m-6)+7(m-3)=14-10 equation: 



-3(2m-6)+7(m-3)=14-10

We move all terms to the left:

-3(2m-6)+7(m-3)-(14-10)=0

We add all the numbers together, and all the variables

-3(2m-6)+7(m-3)-4=0

We multiply parentheses

-6m+7m+18-21-4=0

We add all the numbers together, and all the variables

m-7=0

We move all terms containing m to the left, all other terms to the right

m=7

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