-3(2n+4)=6(n-2)

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Solution for -3(2n+4)=6(n-2) equation: 



-3(2n+4)=6(n-2)

We move all terms to the left:

-3(2n+4)-(6(n-2))=0

We multiply parentheses

-6n-(6(n-2))-12=0



We calculate terms in parentheses: -(6(n-2)), so:

6(n-2)

We multiply parentheses

6n-12

Back to the equation:

-(6n-12)



We get rid of parentheses

-6n-6n+12-12=0

We add all the numbers together, and all the variables

-12n=0

n=0/-12

n=0

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