-3(2n-5)=1/2(-12n+30

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Solution for -3(2n-5)=1/2(-12n+30 equation: 



-3(2n-5)=1/2(-12n+30

We move all terms to the left:

-3(2n-5)-(1/2(-12n+30)=0



Domain of the equation: 2(-12n+30)!=0

n∈R



We multiply parentheses

-6n-(1/2(-12n+30)+15=0

We multiply all the terms by the denominator


-6n*2(-12n+30)+15-(1=0

We add all the numbers together, and all the variables

-6n*2(-12n+30)=0

Wy multiply elements

-12n^2(-=0

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