-3(2q+4)+7q=19

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Solution for -3(2q+4)+7q=19 equation: 



-3(2q+4)+7q=19

We move all terms to the left:

-3(2q+4)+7q-(19)=0

We add all the numbers together, and all the variables

7q-3(2q+4)-19=0

We multiply parentheses

7q-6q-12-19=0

We add all the numbers together, and all the variables

q-31=0

We move all terms containing q to the left, all other terms to the right

q=31

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