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-3(2r-1)=3r-2(1+5r)
We move all terms to the left:
-3(2r-1)-(3r-2(1+5r))=0
We add all the numbers together, and all the variables
-3(2r-1)-(3r-2(5r+1))=0
We multiply parentheses
-6r-(3r-2(5r+1))+3=0
We calculate terms in parentheses: -(3r-2(5r+1)), so:We get rid of parentheses
3r-2(5r+1)
We multiply parentheses
3r-10r-2
We add all the numbers together, and all the variables
-7r-2
Back to the equation:
-(-7r-2)
-6r+7r+2+3=0
We add all the numbers together, and all the variables
r+5=0
We move all terms containing r to the left, all other terms to the right
r=-5
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