-3(2r-4)=-2(10r+7)

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Solution for -3(2r-4)=-2(10r+7) equation: 



-3(2r-4)=-2(10r+7)

We move all terms to the left:

-3(2r-4)-(-2(10r+7))=0

We multiply parentheses

-6r-(-2(10r+7))+12=0



We calculate terms in parentheses: -(-2(10r+7)), so:

-2(10r+7)

We multiply parentheses

-20r-14

Back to the equation:

-(-20r-14)



We get rid of parentheses

-6r+20r+14+12=0

We add all the numbers together, and all the variables

14r+26=0

We move all terms containing r to the left, all other terms to the right

14r=-26

r=-26/14

r=-1+6/7

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