-3(2r-5)=2(9-4r)

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Solution for -3(2r-5)=2(9-4r) equation:



-3(2r-5)=2(9-4r)
We move all terms to the left:
-3(2r-5)-(2(9-4r))=0
We add all the numbers together, and all the variables
-3(2r-5)-(2(-4r+9))=0
We multiply parentheses
-6r-(2(-4r+9))+15=0
We calculate terms in parentheses: -(2(-4r+9)), so:
2(-4r+9)
We multiply parentheses
-8r+18
Back to the equation:
-(-8r+18)
We get rid of parentheses
-6r+8r-18+15=0
We add all the numbers together, and all the variables
2r-3=0
We move all terms containing r to the left, all other terms to the right
2r=3
r=3/2
r=1+1/2

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